10x^2+360x=0

Solution for 10x^2+360x=0 equation:

10x^2+360x=0

a = 10; b = 360; c = 0;
Δ = b2-4ac
Δ = 3602-4·10·0
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(360)-360}{2*10}=\frac{-720}{20}
=-36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(360)+360}{2*10}=\frac{0}{20}
=0
$